در این قسمت یک برنامه ء کوچک که کاملا تحت خط فرمان هست و خودم نوشتم رو گذاشتم . برای افرادی که تازه رفتن سراغ پایتون و مبتدی ها بدرد می خوره وساطای سورس کد تمام توضیحات گذاشته شده .

توصیه من اینه که اول همه متن رو به یک نرم افزار بدرد بخور مثل notepad++ یا programmer's notepad انتقال بدین بعد روش کار کنید. سورس کد کاملا سالمه و کار می کنه . (در واقع یک سری عدد تصادفی بین دو عدد تصادفی دیگه تولید می کنه که باید توسط کاربر حدس زده بشه)

#!usr/bin/python
#Filename : guess.py
#coded by Mojtaba Eshghi
import random
print('hello, my name is jack')
print('Mr. Eshghi has written me, actually he is my father')
print('')
print('I am the guess programm')
print('check your chance to see if you are lucky or not')
aa=['0','1','second','third','forth','fifth']#the mistake was here and I solved it!
#don't confuse baby, these are only some strings guys
so='sorry baby, your guess was wrong this time'
si='good your guess was correct in lower than 4 tries, you\'re lucky today'
sd='ah, come on, your guess was correct but it was too late for that '
fg=''' great, congratulations for you, you guessed the number in first try
                      you are so lucky man!!!'''
nt='not too bad, but a bit late, don\'t worry you will be lucky the next day'
aw='it\'s awful, '
t=type('')
for i in range(1,100):
    a=random.randint(8,10)
    b=random.randint(10,13)
    c=random.randint(a,b)
    if i>1 and i<6:
        print('be carefull this is your ',aa[i],' try')
        #be careful about duplicate identifier of a (first a was list and second integer)
    if i>5 :
        print('Carefull man! your guess is taking so long')
    print('I\'m thinking about a number between ',a,' and ',b)
    print('guess what is it?')
    g=input() #look, here we should convert string g into the integer g
    if g=='exit':
        print('good bye to you!!!')
        break
    s=type(g)
    if s==t:
        print('you entered an string value instead of integer!!! please enter an int')
        #here we correct our mistake
        g=0 #we give g and incorrect value to end up this loop and go to the loop that happens next time,
    g=int(g)
    if g==c :
        if i==1:
            print(fg)
        if i in range(1,4):
            print(si)
        if i in range(4,6):
            print(nt)
        if i in range(6,12):
            print(aw,sd)
    if g!=c :
        print(so)
        print('the correct answer is   ',g)

#but be wise a problem is still steady guess what is that? hah? this program is guess program!
#if you type any string except "exit" in the program command line you will get this error

#Traceback (most recent call last):
#  File "g.py", line 32, in
#    g=int(g)
#ValueError: invalid literal for int() with base 10: 'p'

#this error is because the value of g(that is now an str (because we want to enter an str instead of int to see what problems may happen))
#the value of g is str but int() function in line 32  cann't deal with those strings that do not carry any int-like data in their body.
#so what can we do now? hah, a trick baby, a trick!
#we use this to see what is the type of a value "type()" and now we do so, but we save the result to use with "if" conditional statement
#we should put this at starting part of the progarm as initialization to a value, somewhere like in line 19;
#t=type('') #this will give t the sring value ''
#and we should put the following part exactly in line 35
#s=type(g) #and finally with an "if" conditional statement in line 36 we do it...

#*********************************************Mojtaba Eshghi**********************************************
   
           
           
   
   
 

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